from the practice book." If R*a=a*(4/5), then R= A)2/3B)4/5C)1D)5/4E)Cannot be determined."Shit blew my mind.Yall take a stab at it. Ill come back with the answer. [Edited on May 9, 2014 at 11:09 AM. Reason : .]
5/9/2014 11:07:45 AM
easy
5/9/2014 11:37:12 AM
well...this is awkward. http://www.wolframalpha.com/input/?i=R*a%3Da*%284%2F5%29%2C+solve+R
5/9/2014 12:12:23 PM
assuming the question is as you stated and nothing more, i already posted the answer
5/9/2014 12:42:31 PM
are you two serious?
5/9/2014 1:12:02 PM
i am very serious
5/9/2014 1:25:11 PM
I know and do see that. But why Wolfram did not Note any assumption is quite careless.
5/9/2014 2:08:14 PM
^ yeah, pretty surprised too.they made up their own assumption that a != 0.remember, 0 is always a legit value for any variable, unless otherwise indicated.i love gre/sat questions... if you have more where you are confused, please do post, i demolished the gre
5/9/2014 2:48:51 PM