So one of my coworkers kids has some probability problems to work on. It's been a while since I had to deal with this stuff and I dont want to look like an idiot and get it wrong.

Can anyone with more time than myself help me out with these problems? ( and how you solved them i.e combinations and permutations used.

Thanks in advance...

A bag contains 6 red balls and 4 blue balls. 3 balls are drawn. In how many ways can the three be drawn so that all are blue? At least one is blue? And all are the same color?

From the digits 0,2,3,5,7,9 how many 3 digit numbers are possible if no digit can be repeated ( 0 cant be the first number ) If digits can be repeated? Consist of only odd digits without repititions?

If 3 men and 3 women are seated in a row of 6 seats in how many ways can they sit? Or sit if the men are to the right of the women? Or if the men and women alternate?

12/11/2006 10:53:56 AM

Quote :

"From the digits 0,2,3,5,7,9 how many 3 digit numbers are possible if no digit can be repeated ( 0 cant be the first number ) If digits can be repeated? Consist of only odd digits without repititions?"

No repeat: 5 x 5 x 4 = 100

Repeat: 5 x 6 x 6 = 180

Odd only, no repeat: 4 x 3 x 2 = 24 (0,2 not odd)

How it's done: Avaliable # x New Avaliable # x ......


I'd have to do some refresher reading before I could answer the others.

12/11/2006 11:17:49 AM