How many grams of 50 wt % NaOH (FM 40.00) should be diluted to 1.00 L to make 0.10 M NaOH?

5/29/2006 10:30:49 PM

look in your solution guide OR visit Chem tutorial...that advice got me through two semester of that CH stuff

5/29/2006 10:32:57 PM

no solution guide, anyone else?

5/29/2006 10:33:46 PM

I'd be able to explain the answer if this were Spring 2004. Alas, that semester is long gone.

5/29/2006 11:18:43 PM

0.1 M NaOH in 1.00 L means there are 0.1 moles in the solution. (I think thats right)

Well if you knows the # of moles you know the # of atoms and you know the weight of a NaOH atom so you know the weight of NaOH you need. However you only have 50 w% so you need 2*Mass(NaOH) of the 50 w% solution.

5/29/2006 11:25:54 PM

thank you! that worked

5/29/2006 11:31:49 PM

that part with the moler stuff was the only part I wasn't sure about (it has been ~4 years since I've had chemistry)

5/29/2006 11:42:51 PM

this shit's easy, as i have gotten the tougher proceeding problems....but i cant get this one to save my life....2 submissions left.....any help would be appreciated



A solution is prepared by dissolving 1.7 g CaCl2 in 137.0 g water. What is the freezing point of this solution. Note: kf for water is 1.86oC/m

5/30/2006 9:17:44 PM

Water freezes at 0 and goes up 1.86 C/mole.

1.7 g CaCl2 |  mole         |               | g H20 |  1.86 C
----------------------------------------------------------
              |    g CaCl2   |  137 g H2O |  L H20 |   mole

5/30/2006 10:01:29 PM

the formula for this problem is:

delta*Tf = i*kf*m
=3*-1.86*.117
=-.65 degree Celsius

i got it....my i was wrong...thanks tho

5/30/2006 10:24:29 PM