what happens when a square wave is applied to an RC circuit?

2/15/2006 11:02:48 PM

You need to create sperate equations for each section of the square wave. Remember V(0+)=V(0-), so the initial voltage of one period is going to be the voltage at that time from the previous period (plug in t in the equation you got)

2/15/2006 11:29:21 PM

2/15/2006 11:34:22 PM

2/15/2006 11:37:03 PM

I can find the voltage across the capacitor for the first voltage level and the second voltage level separately, is the voltage on the capacitor after the full time period equal to the sum? I dont see how the V(0+)=V(0-) helps...

time to switch majors i guess

2/15/2006 11:38:10 PM

You are applying V(0+)=V(0-) (voltage across a capacitor cannot change instantaneously) to the time that the source voltage changes.

Here is the equation for voltage across a capacitor:

V0 is your initial voltage and Vdc is the steady state voltage (when time goes to infinity)

Plug in the time when the voltage changes into the previous period's equation, and use that as the initial condition in the equation for after the voltage changes.

I don't think you can use one equation to describe it. You will have to use seperate equations for each time period.

2/16/2006 12:08:35 AM

you should go to bed

2/16/2006 12:18:10 AM

ok got it now. thanks for the help, you saved me

2/16/2006 2:09:05 PM