for the Ix of the given sections i got 4(1.32e6 + 1.36e3(109.5^2)), did any one else get this and if not how did you do it thanks

11/19/2005 11:20:56 PM

oh, i took CE 213, i'm above that shit.

11/19/2005 11:28:08 PM

too bad it is 214

11/19/2005 11:30:46 PM

213 is 214 and 215. it's for the people who are too smart to take them seperatley.

11/19/2005 11:32:13 PM

my bad then never heard of it

11/19/2005 11:33:15 PM

what's the problem?

11/19/2005 11:33:44 PM

Quote :

"213 is 214 and 215. it's for the people who are too smart to take them seperatley."

Riiight

11/19/2005 11:38:02 PM

looks right but don't forget the I part.

11/20/2005 12:13:20 AM

here was my entire equation Ix=((1/12)(75)(20^3))2 + ((1/12)(15)(275^3)) + the equation from the first post does this look right

11/20/2005 12:18:56 AM

everytime i use this formula i get a different answer from the back of the book

11/20/2005 12:29:26 AM

anybody figure out why my equation is wrong

11/20/2005 2:08:04 AM

I can't see the problem, but do you need to use the paralell axis theorom on it?


You've got the Ix part... but do you need to use 1/12 bh^3 + Ad^2 ?


Just a though.... like I said... I have absolutely no idea what the section looks like you're trying to find

[Edited on November 20, 2005 at 10:46 AM. Reason : sfsd]

11/20/2005 10:46:11 AM

yeah you have to use the parallel axis theorem, but all i have to look for is Ix and i guess i need to due something else to my formula

11/20/2005 2:09:37 PM

maybe you should post the problem

11/20/2005 3:16:10 PM